Compound A reacts with $\mathrm{NH}_4 \mathrm{Cl}$ and forms a compound B . Compound B reacts with $\mathrm{H}_2 \mathrm{O}$ and excess of $\mathrm{CO}_2$ to form compound C which on passing through or reaction with saturated NaCl solution forms sodium hydrogen carbonate. Compound A. B and C, are respectively.