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JEE-ADVANCED-2015
PAPER 1
Question
Consider a hydrogen atom with its electron in the $\mathrm{n}^{\text {th }}$ orbital. An electromagnetic radiation of wavelength 90 nm is used to ionize the atom. If the kinetic energy of the ejected electron is 10.4 eV , then the value of $n$ is $(\mathrm{hc}=1242 \mathrm{eV} \mathrm{nm})$
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Question Tags
JEE Advance
Physics
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