Report Issue

JEE MAIN 2025
28-01-2025 SHIFT-1
Question
Consider a long thin conducting wire carrying a uniform current I. A particle having mass "M" and charge "q" is released at a distance "a" from the wire with a speed ${{\rm{v}}_{\rm{o}}}$ along the direction of current in the wire. The particle gets attracted to the wire due to magnetic force. The particle turns round when it is at distance x from the wire. The value of x is [${\mu _0}$ is vacuum permeability]
Select the correct option:
A
$a\left[ {1 - \frac{{m{v_0}}}{{2q{\mu _0}{\rm{I}}}}} \right]$
B
$\frac{a}{2}$
C
$a{e^{ - \frac{{4\pi m{v_0}}}{{{{\rm{q}}_{\rm{o}}}{\rm{I}}}}}}$
D
$a\left[ {1 - \frac{{{\rm{mv}}}}{{{\rm{q}}{\mu _0}{\rm{I}}}}} \right]$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Physics
Hard
Start Preparing for JEE with Competishun
Video Solution
BY competishun
Video Solution
Watch Solution