Consider the lines $$ \begin{aligned} & L_1: \frac{x+1}{3}=\frac{y+2}{1}=\frac{z+1}{2} \\ & L_2: \frac{x-2}{1}=\frac{y+2}{2}=\frac{z-3}{3} \end{aligned} $$
The distance of the point (1, 1, 1 ) from the plane passing through the point ( $-1,-2,-1$ ) and whose normal is perpendicular to both the lines $\mathrm{L}_1$ and $\mathrm{L}_2$ is