Consider three boxes, each containing 10 balls labelled 1, 2, ...,10. Suppose one ball is randomly drawn from each of the boxes. Denote by ni, the label of the ball drawn from the ith box, (i = 1, 2, 3). Then, the number of ways in which the balls can be chosen such that $\mathrm{n}_1<\mathrm{n}_2<\mathrm{n}_3$ is
Select the correct option:
A
(1) 240
B
120
C
164
D
82
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Collecting different labels of balls drawn= $10 \times 9 \times 8$ Now, arrangement is not required so $\frac{10 \times 9 \times 8}{3!}=120$
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