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JEE MAIN 2025
28-01-2025 SHIFT-1
Question
If $\int_{ - \frac{\pi }{2}}^{\frac{\pi }{2}} {\frac{{96{x^2}{{\cos }^2}x}}{{\left( {1 + {e^x}} \right)}}} {\rm{d}}x = \pi \left( {\alpha {\pi ^2} + \beta } \right),\alpha ,\beta \in $ , then ${(\alpha + \beta )^2}$ equals
Select the correct option:
A
196
B
100
C
144
D
64
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Easy
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