Diborane (B₂H₆) reacts independently... | p-Block Elements

JEE MAIN 2019

08-04-2019 S1

Question

Diborane $\left(\mathrm{B}_2 \mathrm{H}_6\right)$ reacts independently with $\mathrm{O}_2$ and $\mathrm{H}_2 \mathrm{O}$ to produce, respectively:

Select the correct option:

$\mathrm{H}_3 \mathrm{BO}_3$ and $\mathrm{B}_2 \mathrm{O}_3$

$\mathrm{HBO}_2$ and $\mathrm{H}_3 \mathrm{BO}_3$

$\mathrm{B}_2 \mathrm{O}_3$ and $\mathrm{H}_3 \mathrm{BO}_3$

$\mathrm{B}_2 \mathrm{O}_3$ and $\left[\mathrm{BH}_4\right]^{-}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{aligned} & \mathrm{B}_2 \mathrm{H}_6+3 \mathrm{O}_2 \longrightarrow \mathrm{~B}_2 \mathrm{O}_3+3 \mathrm{H}_2 \mathrm{O} \\ & \mathrm{B}_2 \mathrm{H}_6+6 \mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{H}_3 \mathrm{BO}_3+6 \mathrm{H}_2\end{aligned}$

Question Tags

JEE Main

Chemistry

Easy

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