DEFINITE INTEGRATION_JEE MAIN_12-01-2019_S2 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE MAIN 2019

12-01-2019 S2

Question

The integral $\int_1^e\left\{\left(\frac{x}{e}\right)^{2 x}-\left(\frac{e}{x}\right)^x\right\} \log _e x d x$ is equal to

Select the correct option:

$\frac{3}{2}-e-\frac{1}{2 e^2}$

$-\frac{1}{2}+\frac{1}{e}-\frac{1}{3 e^2}$

$\frac{1}{2}-e-\frac{1}{e^2}$

$\frac{3}{2}-\frac{1}{e}-\frac{1}{2 e^2}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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