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JEE MAIN 2022
29-06-2022 S2
Question
Elevation in boiling point for 1.5 molal solution of glucose in water is 4 K . The depression in freezing point for 4.5 molal solution of glucose in water is 4 K . The ratio of molal elevation constant to molal depression constant $\left(\mathrm{Kb}_{\mathrm{b}} / \mathrm{K}_{\mathrm{f}}\right)$ is $\_\_\_\_$ .
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Solution
$\begin{aligned} & \Delta \mathrm{T}_{\mathrm{b}}=\mathrm{iK}_{\mathrm{b}} \mathrm{m} \\ & \Delta \mathrm{T}_{\mathrm{f}}=\mathrm{iK}_{\mathrm{f}} \mathrm{m} \\ & \frac{4}{4}=\frac{\mathrm{K}_{\mathrm{b}} 1.5}{\mathrm{~K}_{\mathrm{f}} 4.5} \\ & \frac{\mathrm{~K}_{\mathrm{b}}}{\mathrm{K}_{\mathrm{f}}}=3\end{aligned}$
Question Tags
JEE Main
Chemistry
Easy
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