For a perfect gas...| KTG & THERMODYNAMICS| JEE-Main 2022

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JEE MAIN 2022

27-06-2022 S2

Question

For a perfect gas, two pressures P1 and P2 are shown in figure. The graph shows:

Select the correct option:

$P_1>P_2$

P1 < P2

P1 = P2

Insufficient data to draw any conclusion

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{aligned} & \mathrm{PV}=\mathrm{nRT} \\ & \frac{\mathrm{V}}{\mathrm{T}}=\frac{\mathrm{nR}}{\mathrm{P}} \\ & \frac{\mathrm{nR}}{\mathrm{P}_1}<\frac{\mathrm{nR}}{\mathrm{P}_2} \\ & \mathrm{P}_2<\mathrm{P}_1\end{aligned}$

Question Tags

JEE Main

Physics

Easy

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