For a reaction at equilibrium A(g) ⇌ B(g) + 1/2 C(g)... | Chemical Equilibrium

JEE-Main 2022

24-6-22_S1

Question

For a reaction at equilibrium $$ \mathrm{A}(\mathrm{~g}) \rightleftharpoons \mathrm{B}(\mathrm{~g})+\frac{1}{2} \mathrm{C}(\mathrm{~g}) $$ the relation between dissociation constant (K), degree of dissociation ( $\alpha$ ) and equilibrium pressure (p) is given by :

Select the correct option:

$\mathrm{K}=\frac{\alpha^{\frac{1}{2}} \mathrm{p}^{\frac{3}{2}}}{\left(1+\frac{3}{2} \alpha\right)^{\frac{1}{2}}(1-\alpha)}$

$\mathrm{K}=\frac{\alpha^{\frac{3}{2}} \mathrm{p}^{\frac{1}{2}}}{(2+\alpha)^{\frac{1}{2}}(1-\alpha)}$

$K=\frac{(\alpha p)^{\frac{3}{2}}}{\left(1+\frac{3}{2} \alpha\right)^{\frac{1}{2}}(1-\alpha)}$

$K=\frac{(\alpha p)^{\frac{3}{2}}}{(1+\alpha)(1-\alpha)^{\frac{1}{2}}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution