For a reaction, given below is the graph of $\ln \mathrm{k}$ vs $\frac{1}{\mathrm{~T}}$. The activation energy for the reaction is equal to cal mol-1. (Nearest integer). (Given : $\mathrm{R}=2 \mathrm{cal} \mathrm{K}^{-1} \mathrm{~mol}^{-1}$ )
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