Electrostatics JEE Main 2025 Solution

JEE MAIN 2025

22-01-2025 SHIFT-2

Question

For a short dipole placed at origin $O$, the dipole moment $P$ is along $x$-axis, as shown in the figure. If the electric potential and electric field at $A$ are $V_0$ and $E_0$, respectively, then the correct combination of the electric potential and electric field, respectively, at point B on the $y$-axis is given by

Select the correct option:

$V_0 \text { and } \frac{E_0}{4}$

$\text { zero and } \frac{E_0}{8}$

$\frac{V_0}{2} \text { and } \frac{E_0}{16}$

$\text { zero and } \frac{E_0}{16}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

\begin{aligned} & E_A=\frac{2 k P}{r^3}=E_0 \& V_A=\frac{k P}{r^2}=v_0 \\ & E_B=\frac{k P}{(2 r)^3}=\frac{E_0}{16} \& V_B=\frac{k \vec{P} \cdot \hat{r}}{r^2}=0 \end{aligned}

Question Tags

JEE Main

Physics

Easy

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