For Ideal heat Temperature |KTG&THERMODYNAMICSJEEMain2021

JEE MAIN 2021

16-03-2021 S2

Question

For an ideal heat engine, the temperature of the source is 127°C. In order to have 60% efficiency the temperature of the sink should be _______°C. (Round off to the Nearest Integer)

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Solution

$\begin{aligned} & n=0.60=1=\frac{T_L}{T_H} \\ & \frac{T_L}{T_H}=0.4 \Rightarrow T_L=0.4 \times 400 \\ & =160 \mathrm{~K} \\ & =-113^{\circ} \mathrm{C}\end{aligned}$

Question Tags

JEE Main

Physics

Easy

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