For an isosceles prism of angle $A$ and refractive index $\mu$, it is found that the angle of minimum deviation $\delta_{\mathrm{m}}=\mathrm{A}$. Which of the following options is/are correct?
Select ALL correct options:
A
At minimum deviation, the incident angle $i_1$ and the refracting angle $r_1$ at the first refracting surface are related by $r_1=\left(i_1 / 2\right)$
B
For this prism, the refractive index $\mu$ and the angle of prism A are related as $\mathrm{A}=\frac{1}{2} \cos ^{-1}\left(\frac{\mu}{2}\right)$
C
For the angle of incidence $\mathrm{i}_1=\mathrm{A}$, the ray inside the prism is parallel to the base of the prism
D
For this prism, the emergent ray at the second surface will be tangential to the surface when the angle of incidence at the first surface is $i_1=\sin ^{-1}\left[\sin A \sqrt{4 \cos ^2 \frac{A}{2}-1}-\cos A\right]$
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