For particle P revolving... |JEE Main 2023

JEE MAIN 2023

29-1-2023 S2

Question

For particle P revolving round the centre O with radius of circular path r and angular velocity , as shown in below figure, the projection of OP on the x-axis at time t is

Select the correct option:

$x(t)=r \cos \left(\omega t+\frac{\pi}{6}\right)$

$x(t)=r \cos (\omega t)$

$x(t)=r \sin \left(\omega t+\frac{\pi}{6}\right)$

$x(t)=r \cos \left(\omega t-\frac{\pi}{6} \omega\right)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Medium

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