Report Issue

JEE MAIN_2021_
27-07-21_S2
Question
For the cell $$ \mathrm{Cu}(\mathrm{~s})\left|\mathrm{Cu}^{2+}(\mathrm{aq})(0.1 \mathrm{M}) \| \mathrm{Ag}^{+}(\mathrm{aq})(0.01 \mathrm{M})\right| \mathrm{Ag}(\mathrm{~s}) $$ the cell potential $\mathrm{E}_1=0.3095 \mathrm{~V}$ For the cell $$ \mathrm{Cu}(\mathrm{~s})\left|\mathrm{Cu}^{2+}(\mathrm{aq})(0.01 \mathrm{M}) \| \mathrm{Ag}^{+}(\mathrm{aq})(0.001 \mathrm{M})\right| \mathrm{Ag}(\mathrm{~s}) $$ the cell potential = $\_\_\_\_$ $\times 10^{-2} \mathrm{~V}$. (Round off the Nearest Integer). [Use : $\frac{2.303 \mathrm{RT}}{\mathrm{F}}=0.059$ ]
Write Your Answer
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Chemistry
Easy
Start Preparing for JEE with Competishun