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JEE MAIN 2023
25-01-23 S1
Question
For the first order reaction $\mathrm{A} \rightarrow \mathrm{B} \mathrm{Br}$ the half life is 30 mm . The time taken for $75 \%$ completion of the reaction is $\_\_\_\_$ mm. (Nearest mteger)
Given: $\log 2=0.3010, \log 3=0.4771, \log 5=0.6989$
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Solution
$\mathrm{t}_{1 / 2}=\mathrm{T} 50=30 \mathrm{~min}, \mathrm{~T}_{75}=2 \mathrm{t}_{1 / 2}=30 \times 2=60 \mathrm{~min}$
Question Tags
JEE Main
Chemistry
Easy
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