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JEE Advance 2021
Paper-2
Question
For the reaction, $\mathbf{X}(s) \rightleftharpoons \mathbf{Y}(s)+\mathbf{Z}(g)$, the plot of $\ln \frac{\mathrm{p}_{\mathrm{z}}}{\mathrm{p}^{\Theta}}$ versus $\frac{10^4}{\mathrm{~T}}$ is given below (in solid line), where pz is the pressure (in bar) of the gas Z at temperature T and $\mathrm{p}^{\ominus}=1$ bar.

$$ \text { (Given, } \frac{d(\ln K)}{d\left(\frac{1}{T}\right)}=-\frac{\Delta H^{\ominus}}{R} \text {, where the equilibrium constant, } K=\frac{p_z}{p^{\ominus}} \text { and the gas constant, } $$
The value of $\Delta \mathrm{S}^{\ominus}$ (in $\mathrm{J} \mathrm{K}^{-1} \mathrm{~mol}^{-1}$ ) for the given reaction, at 1000 K is $\_\_\_\_$ .
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Question Tags
JEE Advance
Chemistry
Easy
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