Four identical particles located |GravitationJEEMain2019..

JEE MAIN 2019

08-04-2019 S1

Question

Four identical particles of mass M are located at the corners of a square of side ‘a’. What should be their speed if each of them revolves under the influence of others’ gravitational field in a circular orbit circumscribing the square?

Select the correct option:

$1.41 \sqrt{\frac{G M}{a}}$

$1.16 \sqrt{\frac{G M}{a}}$

$1.21 \sqrt{\frac{G M}{a}}$

$1.35 \sqrt{\frac{G M}{a}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Hard

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