Given below are two statements :
Statement I : $[\mathrm{Ni}(\mathrm{CN}) 4]^2$ is square planar and diamagnetic complex. with $\mathrm{dsp}^2$ hybridization for Ni but $[\mathrm{Ni}(\mathrm{CO}) 4]$ is tetrahedral. paramagnetic and with $s p^3-$hybridication for Ni.
Statement II: $\left[\mathrm{NiCl}_4\right]^{2-}$ and $[\mathrm{Ni}(\mathrm{CO}) 4]$ both have same d-electron configuration have same geometry and are paramagnetic.
In light the above statements. choose the correct answer form the options given below: