Given that slope tangent |DifferentialEquationsJEEMain2019

JEE MAIN 2019

08-04-2019 S2

Question

Given that the slope of the tangent to a curve $y=y(x)$ at any point ( $x, y$ ) is $\frac{2 y}{x^2}$. If the curve passes through the centre of the circle $x^2+y^2-2 x-2 y=0$, then its equation is

Select the correct option:

$x \log _e|y|=-2(x-1)$

$x \log _e|y|=x-1$

$x \log _e|y|=2(x-1)$

$x^2 \log _e|y|=-2(x-1)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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