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JEE MAIN 2025
02-04-2025 SHIFT-2
Question
Identify the characteristics of an adiabatic process in a monoatomic gas.
(A) Internal energy is constant.
(B) Work done in the process is equal to the change in internal energy.
(C) The product of temperature and volume is a constant.
(D) The product of pressure and volume is a constant.
(E) The work done to change the temperature from $T_{1}$ to $T_{2}$ is proportional to $\left(T_{2}-T_{1}\right)$.
Choose the correct answer from the options given below :
Select the correct option:
A
(B), (D) only
B
(A), (C), (E) only
C
(B), (E) only
D
(A), (C), (D) only
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$Q=\Delta U+W=0 \Rightarrow-\Delta U=W$
$W D=-n C_{v} \Delta T \Rightarrow|W D|=n C_{v} \Delta T \propto T_{2}-T_{1}$
$\therefore B$ & $E$ [Only possibility]
Question Tags
JEE Main
Physics
Easy
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