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JEE MAIN 2024
04-04-2024 S1
Question
If 2 and 6 are the roots of the equation $\mathrm{ax}^2+\mathrm{bx}+1=0$, then the quadratic equation, whose roots are $\frac{1}{2 a+b}$ and $\frac{1}{6 a+b}$, is :
Select the correct option:
A
$2 x^2+11 x+12=0$
B
$4 x^2+14 x+12=0$
C
$x^2+10 x+16=0$
D
$x^2+8 x+12=0$
✓ Correct! Well done.
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Solution
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Question Tags
JEE Main
Mathematics
Easy
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