Report Issue

JEE MAIN 2021
25-02-2021 S2
Question
If a compound AB dissociates to the extent of $75 \%$ in an aqueous solution, the molality of the solution which shows a 2.5 K rise in the boiling point of the solution is $\_\_\_\_$ molal.
$$ \left[\mathrm{K}_{\mathrm{b}}=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right]
$$
Write Your Answer
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$$ \begin{aligned} & \alpha=0.75, n=2 \\ & i=1-\alpha+n \alpha=1-0.75+2 \times 0.75=1.75 \\ & \Delta T_b=i k_b m \end{aligned} $$ or, $2.5=1.75 \times 0.52 \times \mathrm{m}$
or, $\mathrm{m}=\frac{2.5}{1.75 \times 0.52}=2.74$
$\therefore \quad$ nearest integer answer will be 3
Question Tags
JEE Main
Chemistry
Easy
Start Preparing for JEE with Competishun