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JEE MAIN 2020
08-01-20 S2
Question
If a line, $y=m x+c$ is a tangent to the circle $\ldots(x-3)^2+y^2=1$ and it is perpendicular to a line $L_1$, where $L_1$ is the tangent to the circle, $x^2+y^2=1$ at the point $\left(\frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}}\right)$; then
Select the correct option:
A
$c^2+6 c+7=0$
B
$c^2-7 c+6=0$
C
$c^2+7 c+6=0$
D
$c^2-6 c+7=0$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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