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JEE-MAIN 2020
03-09-2020 S2
Question
If a semiconductor photodiode can detect a photon with a maximum wavelength of 400 nm, then its band gap energy is Planck's constant $\mathrm{h}=6.63 \times 10^{-34} \mathrm{~J} . \mathrm{s}$. Speed of light $\mathrm{c}=3 \times 10^8 \mathrm{~m} / \mathrm{s}$
Select the correct option:
A
1.1 eV
B
2.0 eV
C
3.1 eV
D
1.5 eV
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Solution
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Question Tags
JEE Main
Physics
Easy
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