$\begin{aligned} & \mathrm{F}=\frac{1}{4 \pi \epsilon_0} \frac{\mathrm{e}^2}{\mathrm{r}^2} \\ & \mathrm{E}=\frac{\mathrm{hc}}{\lambda} \\ & {\left[\frac{\mathrm{e}^2}{4 \pi \varepsilon_0} \times \frac{1}{\mathrm{hc}}\right]=\frac{\mathrm{Fr}^2}{\mathrm{E} \lambda}=\left(\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^0\right)}\end{aligned}$