If $f(x)=\left\{\begin{array}{cc}x+a, & x \leq 0 \\ |x-4|, & x>0\end{array}\right.$ and $g(x)=\left\{\begin{array}{cc}x+1, & x<0 \\ (x-4)^2+b, & x \geq 0\end{array}\right.$ are continuous on $R$, then $(g \circ f)(2)+(f \circ g)(-2)$ is equal to :
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