If $\int \frac{\sqrt{1-x^2}}{x^4} d x=A(x)\left(\sqrt{1-x^2}\right)^m+C$, for a suitable chosen integer $m$ and a function $A(x)$, where $C$ is a constant of integration, then $(\mathrm{A}(\mathrm{x}))_{\sim \sim}^{\mathrm{m}}$ equals:
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