Constant of integration |NDEFINITE INTEGRATION|JEE MAIN 2019

JEE MAIN 2019

11-01-2019 S2

Question

If $\int \frac{x+1}{\sqrt{2 x-1}} d x=f(x) \sqrt{2 x-1}+C$, where $C$ is a constant of integration, then $f(x)$ is equal to :

Select the correct option:

$\frac{1}{3}(x+1)$

$\frac{1}{3}(x+4)$

$\frac{2}{3}(x-4)$ (

$\frac{2}{3}(x+2)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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