If ∫₋₀.₁₅^₀.₁₅ |100x²−1| dx = k/3000,... | Definite Integration | JEE Main

JEE MAIN 2023

12-04-2023 S1

Question

If $\int_{-0.15}^{0.15}\left|100 \mathrm{x}^2-1\right| \mathrm{dx}=\frac{\mathrm{k}}{3000}$, then k is equal to $\_\_\_\_$ .

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JEE Main

Mathematics

Medium

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