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JEE MAIN 2026
28-1-2026 S1
Question
If $\int\left(\frac{1-5 \cos ^2 x}{\sin ^5 x \cos ^2 x}\right) d x=f(x)+\mathrm{C}$, where C is the constant of integration, then $f\left(\frac{\pi}{6}\right)-f\left(\frac{\pi}{4}\right)$ is equal to
Select the correct option:
A
$\frac{1}{\sqrt{3}}(26+\sqrt{3})$
B
$\frac{4}{\sqrt{3}}(8-\sqrt{6})$
C
$\frac{1}{\sqrt{3}}(26-\sqrt{3})$
D
$\frac{2}{\sqrt{3}}(4+\sqrt{6})$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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