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JEE MAIN 2022
27-07-22 S1
Question
If $K_1$ and $K_2$ are the thermal conductivities $L_1$ and $L_2$ are the lengths and $A_1$ and $A_2$ are the cross sectional areas of steel and copper rods respectively such that $\frac{K_2}{K_1}=9, \frac{A_1}{A_2}=2, \frac{L_1}{L_2}=2$. Then for the arrangement as shown in the figure. The value of temperature $T$ of the steel - copper junction in the steady state will be
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Select the correct option:
A
$18^{\circ} \mathrm{C}$
B
$14^{\circ} \mathrm{C}$
C
$45^{\circ} \mathrm{C}$
D
$150^{\circ} \mathrm{C}$
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✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Hard
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