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JEE MAIN 2022
29-07-2022 S2
Question
If momentum of a body is increased by 20%, then its kinetic energy increases by :
Select the correct option:
A
36%
B
40%
C
44%
D
48%
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & P^{\prime}=P+\frac{20}{100} P=1.2 P \\ & \% \text { change in } K E=\frac{K^{\prime}-K}{K} \times 100 \\ & =\left(\frac{\frac{P^2}{2 m}-\frac{P^2}{2 m}}{\frac{P^2}{2 m}}\right) \times 100 \\ & =\left[(1.2)^2-1\right] \times 100 \\ & =44 \%\end{aligned}$
Question Tags
JEE Main
Physics
Easy
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