If the deBroglie wavelength |NUCLEAR PHYSICS

JEE MAIN 2019

11-01-2019 S1

Question

If the deBroglie wavelength of an electron is equal to $10^{-3}$ times the wavelength of a photon of frequency $6 \times 10^{14} \mathrm{~Hz}$, then the speed of electron is equal to : (Speed of light $=3 \times 10^8 \mathrm{~m} / \mathrm{s}$ Planck's constant $=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}$ Mass of electron $=9.1 \times 10^{-31} \mathrm{~kg}$ )

Select the correct option:

$1.7 \times 10^6 \mathrm{~m} / \mathrm{s}$

$1.45 \times 10^6 \mathrm{~m} / \mathrm{s}$

$1.8 \times 10^6 \mathrm{~m} / \mathrm{s}$

$1.1 \times 10^6 \mathrm{~m} / \mathrm{s}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution