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JEE MAIN_2022
26-07-2022_S1
Question
If the function $f(x)=\left\{\frac{\log e\left(1-x+x^2\right)+\log e\left(1+x+x^2\right)}{\sec x-\cos x}, x \in\left(\frac{-\pi}{2}, \frac{\pi}{2}\right)-\{0\}\right.$ is continuous at $x=0$, then $k$ is equal to: ${ }_{x=0}^k$ :
Select the correct option:
A
1
B
-1
C
e
D
00
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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