If the line αx + 4y = √7 touches... |JEE Main 2026

JEE MAIN 2026

21-01-2026 S2

Question

If the line $\alpha x+4 y=\sqrt{7}$, where $\alpha \in \mathbf{R}$, touches the ellipse $3 x^2+4 y^2=1$ at the point P in the first quadrant, then one of the focal distances of $P$ is :

Select the correct option:

$\frac{1}{\sqrt{3}}-\frac{1}{2 \sqrt{11}}$

$\frac{1}{\sqrt{3}}+\frac{1}{2 \sqrt{5}}$

$\frac{1}{\sqrt{3}}-\frac{1}{2 \sqrt{5}}$

$\frac{1}{\sqrt{3}}+\frac{1}{2 \sqrt{7}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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