Area Under Curve_JEE-Main-2021_310821_S1 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE Main 2021

31-08-2021 S1

Question

If the line $y=m x$ bisects the area enclosed by the lines $x=0, y=0, x=3 / 2$ and the curve $y=1+4 x-x^2$, then $12 m$ is equal to $\_\_\_\_$ .

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Solution

Question Tags

JEE Main

Mathematics

Easy

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