Report Issue

JEE MAIN 2024
01-02-2024 S2
Question
If the root mean square velocity of hydrogen molecule at a given temperature and pressure is 2 km/s, the root mean square velocity of oxygen at the same condition in km/s is :
Select the correct option:
A
2.0
B
0.5
C
1.5
D
1.0
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & \mathrm{V}_{\mathrm{rms}}=\sqrt{\frac{3 \mathrm{RT}}{\mathrm{M}}} \\ & \frac{\mathrm{V}_1}{\mathrm{~V}_2}=\sqrt{\frac{\mathrm{M}_2}{\mathrm{M}_1}} \Rightarrow \frac{2}{\mathrm{~V}_2}=\sqrt{\frac{32}{2}} \\ & \mathrm{~V}_2=0.5 \mathrm{~km} / \mathrm{s}\end{aligned}$
Question Tags
JEE Main
Physics
Easy
Start Preparing for JEE with Competishun