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JEE MAIN 2019
09-01-19 S2
Question
If the standard electrode potential for a cell is 2 V at 300 K , the equilibrium constant $(\mathrm{K})$ for the reaction
$\mathrm{Zn}(\mathrm{S})+\mathrm{Cu}^2(\mathrm{aq}) \rightleftharpoons \mathrm{Zn}^{2+}(\mathrm{aq})+\mathrm{Cu}(\mathrm{s})$ at 300 K is approximately
$\left(\mathrm{R}=8 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}, \mathrm{~F}=96000 \mathrm{Cmol}^{-1}\right)$
Select the correct option:
A
$e^{320}$
B
$e^{160}$
C
$e^{-160}$
D
$e^{-80}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Chemistry
Easy
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