Standard electrode potential|Chemical Kinetics|JEE-MAIN2019

JEE MAIN 2019

09-01-19 S2

Question

If the standard electrode potential for a cell is 2 V at 300 K , the equilibrium constant $(\mathrm{K})$ for the reaction $\mathrm{Zn}(\mathrm{S})+\mathrm{Cu}^2(\mathrm{aq})$ 虽署 $\mathrm{Zn}^{2+}(\mathrm{aq})+\mathrm{Cu}(\mathrm{s})$ at 300 K is approximately

Select the correct option:

$\mathrm{e}^{320}$

$\mathrm{e}^{160}$

$\mathrm{e}^{-160}$

$\mathrm{e}^{-80}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\operatorname{InK}=\frac{\mathrm{nFE}^{\circ}{ }_{\text {Cell }}}{\mathrm{RT}} \Rightarrow \operatorname{InK}=\frac{2 \times 96000 \times 2}{8 \times 300}=160$

Question Tags

JEE Main

Chemistry

Easy

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