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JEE MAIN 2022
28-6-2022 S1
Question
If the tangents drawn at the point $\mathrm{O}(0,0)$ and $\mathrm{P}(1+\sqrt{5}, 2)$ on the circle $x^2+y^2-2 x-4 y=0$ intersect at the point $Q$, then the area of the triangle $O P Q$ is equal to
Select the correct option:
A
$\frac{3+\sqrt{5}}{2}$
B
$\frac{4+2 \sqrt{5}}{2}$
C
$\frac{5+3 \sqrt{5}}{2}$
D
$\frac{7+3 \sqrt{5}}{2}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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