The magnitude of resultant vector $R^{\prime}=\sqrt{a^2+b^2+2 a b \cos \theta}$
Here $\mathrm{a}=\mathrm{b}=\mathrm{R}$
Then $R^{\prime}=\sqrt{R^2+R^2+2 R^2 \cos \theta}$
$$
\begin{aligned}
& =R \sqrt{2} \sqrt{1+\cos \theta} \\
& =\sqrt{2} R \sqrt{2 \cos ^2 \frac{\theta}{2}} \\
& =2 R \cos \frac{\theta}{2}
\end{aligned}
$$
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇