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JEE MAIN 2026
21-01-2026 S1
Question
If $x^2+x+1=0$, then the value of $\left(x+\frac{1}{x}\right)^4+\left(x^2+\frac{1}{x^2}\right)^4+\left(x^3+\frac{1}{x^3}\right)^4+\ldots .+\left(x^{25}+\frac{1}{x^{25}}\right)^4$ is:
Select the correct option:
A
128
B
162
C
175
D
145
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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