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JEE MAIN_2019_
10-04-2019-S-1
Question
If $y=y(x)$ is the solution of the differential equation $\frac{\mathrm{dt}}{\mathrm{dx}}=(\tan \mathrm{x}-\mathrm{y}) \sec ^2 \mathrm{x}, \mathrm{x} \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$, such that $\mathrm{y}(0) =0$, then $\mathrm{y}\left(-\frac{\pi}{4}\right)$ is equal to :
Select the correct option:
A
$\frac{1}{e}-2$
B
$\frac{1}{2}-e$
C
e – 2
D
$2+\frac{1}{e}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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