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JEE MAIN 2022
25-06-2022
Question
If $Z=\frac{A^2 B^3}{C^4}$, then the relative error in $Z$ will be
Select the correct option:
A
$\frac{\Delta \mathrm{A}}{\mathrm{A}}+\frac{\Delta \mathrm{B}}{\mathrm{B}}+\frac{\Delta \mathrm{C}}{\mathrm{C}}$
B
$\frac{2 \Delta A}{A}+\frac{3 \Delta B}{B}-\frac{4 \Delta C}{C}$
C
$\frac{2 \Delta A}{A}+\frac{3 \Delta B}{B}+\frac{4 \Delta C}{C}$
D
$\frac{\Delta \mathrm{A}}{\mathrm{A}}+\frac{\Delta \mathrm{B}}{\mathrm{B}}-\frac{\Delta \mathrm{C}}{\mathrm{C}}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Physics
Easy
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