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JEE MAIN 2020
09-01-2020 S2
Question
In a Young's double slit experiment 15 fringes are observed on a small portion of the screen when light of wavelength 500 nm is used. Ten fringes are observed on the same section of the screen when another light source of wavelength $\lambda$ is used. Then the value of $\lambda$ is (in nm ) $\_\_\_\_$ .
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Solution
$\begin{aligned} & 15 \lambda_1=10 \lambda_2 \\ & \lambda_2=1.5 \lambda_1 \\ & \lambda_2=750 \mathrm{~nm}\end{aligned}$
Question Tags
JEE Main
Physics
Medium
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