In a Young's double slit experiment, the slits... | Wave Optics

JEE MAIN 2019

09-01-19 S2

Question

In a Young's double slit experiment, the slits are placed 0.320 mm apart. Light of wavelength $\lambda=500 \mathrm{~nm}$ is incident on the slits. The total number of bright fringes that are observed in the angular range $-30^{\circ} \leq \theta \leq 30^{\circ}$ is

Select the correct option:

640

320

321

641

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$$ \mathrm{N}=\frac{\mathrm{d} \sin \theta}{\lambda}=\frac{0.320 \times 10^{-3}}{500 \times 10^{-9}} \times \frac{1}{2} $$ Number of Bright fringes $=2 \times 320+1=641$

Question Tags

JEE Main

Physics

Medium

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