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JEE MAIN 2019
10-01-2019 S2
Question
In the cell $\mathrm{Pt}(\mathrm{s})\left|\mathrm{H}_2(\mathrm{~g}, 1 \mathrm{bar})\right| \mathrm{HCl}(\mathrm{aq})|\mathrm{AgCl}(\mathrm{s})| \mathrm{Ag}(\mathrm{s}) \mid \mathrm{Pt}(\mathrm{s})$ the cell potential is 0.92 V when a $10^{-6}$ molal HCl solution is used. The standard electrode potential of $\left(\mathrm{AgCl} / \mathrm{Ag} / \mathrm{Cl}^{-}\right)$electrode is:
$\left\{\right.$ Given, $\frac{2.303 R T}{F}=0.06 \mathrm{~V}$ at 298 K$\}$
Select the correct option:
A
0.20 V
B
0.40 V
C
0.76 V
D
0.94 V
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Chemistry
Medium
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